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Rd4!!+
1. Rc4+ Kxb5
2. a4+ Kb6
3. Nd5+ Ka7
4. Rc1 Ne5+
5. Ke2 wins
1. Rc4+ Kb6
2. Nd5+ Kxb5
3. a4 checkmate
1. Rc4+ Kd6
2. Rc1 Ne5+
3. Ke4 wins
1 Rc4 and:
A: 1…Kd6 2 Nf5 Ke5 3 Rc1 and white stops the pawn and keeps black’s knight en prise. Should be sufficient for victory.
B: 1…Kb5 (Kb6 2 Nd5 wins) 2 a4
Kb6 3 Nd5 Ka7 4 Rc1 and white’s advantage should be enough to win.
Insufficient for victory is:
1 bc6?! g1=Q 2 Rc4 Kd6 3 c7 Qf1 4 Kc3 Qc4 5 Kc4 Kc7 and it is not clear that White can win.
-Justin Daniel
Dear Susan,
This one is really beautiful
The idea is extraordinary :
1)Rc4+ Kxb5
2)Nxc6! g1=(Q)
3)Na7+! Qxa7 {if 3)… Kb6 then 4)Nc8+ wins}
4)Rc8! White wins
The line given by the fourth poster wins beautifully although it seems he/she forgot the intermediate 4 a4+ Kb6 and only then 5 Rc8. Who could have visualized the Queen being trapped on a7?!! I think my line still wins although it is not as efficient or beautiful.
-Justin Daniel