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Rdxd5, exd5, Qe3 1-0
1.Rxd5! exd5 2.Qe7+ Ka6 3.Qb4 followed by 4.Qa4++ or 4.Qa5++.
Taimoor’s suggestion fails due to
2. … QxR
To build on the first suggestion:
1. Rdxd5 exd5
2. Qe3+ Ka6
3. Rb4
with the threat of
4. Qa3+
wins for White.
I meant 3 … QxR is a problem for Taimoor’s suggestion. However,
1. Rdxd5 exd5
2. Qe7+ Ka6
3. Rb3
threatening
4. Qa3+
wins for White.
Wayne from Canada:
1.Rbxd5
[If instead 1.Rdxd5 then 1… exd5 2.Qe7+ Ka6 3.Rb3 Qb6 4.Ra3+ Qa5 (4…Kb5 5.Qd7+ Kb4 6.Rb3+ Ka5 7.Qxd5+ Ka6 8.Ra3+ Qa5[] 9.Qc6+ Ka7[] 10.Rxa5+ Kb8[] 11.Rxa8#) ]
Continuing with Black’s move:
1…exd5
Then play could continue:
2.Qe7+ Kb8
[If instead: (a) 2…Ka6 3.Rd3 Qc4 4.Ra3+ Kb6 5.Rb3+ Qxb3 a) 5…Ka6 6.Qa3+ Qa4[] 7.Qxa4#; b) 5…Kc6 6.Qb7+ Kd6 (6…Kc5 7.Qb6#) 7.Rb6+ Kc5 (7…Ke5 8.Qe7+ Kf5 (8…Kf4 9.Qxf7+ Kg4 10.Rg6+ Kxh4 11.Qf3 Qf1+ 12.Kd2 Qe1+ 13.Kxe1 Rhe8+ 14.Kd1 Re1+ 15.Kxe1 Re8+ 16.Kf1 Re1+ 17.Kxe1 h5 18.Qg3#) ) 8.Rc6+ Kd4 9.c3+ Ke5 10.Qe7+ Kf4 (10…Kf5 11.Qxf7+ Kg4[] 12.Rxc4+ dxc4 13.Qf3+ Kxh4[] 14.Qf5 Rxa2 15.g3#) ; ;
(b) 2…Kb6 3.Qb4+ Kc7 (3…Ka6 4.Rd3 Qb5 5.Qd6+ Kb7 6.Rb3 Qxb3 7.axb3+-) 4.Qf4+ Kc8 (4…Kd8 5.Qxf7 Rxa2 6.Rxd5+ Kc8 7.Kb1 Ra4 8.b3 Rxh4 9.Qf5+ Kb7 10.Rd7+ Kb6 11.Rxg7 Rd8 12.Qf7 Rd7 13.Qf8 Rxg7 14.Qxg7-+) 5.Qg4+ f5 6.Qxg7 (6.Qxf5+ Qd7 7.Qf3 Rxa2 8.Kb1 Ra5 9.Qc3+ Qc7 10.Qe1 Qa7 11.Qc3+ Kb8 12.b4 Rb5 13.Kb2 Re8 (13…Qxf2) ) ]
Returning to the main line:
3.Qb4+ Kc8 4.Qg4+ Kb7 5.Qxg7 Rhc8 6.Qxf7+ Kb6 7.c3 Rxa2 8.Rxd5 Rxb2!? 9.Rd3 [9.Kxb2?? Qxc3+ 10.Kb1 Qb3+ 11.Ka1 Rc1#] 9…Rb4 10.Kd2 Rxh4 11.c4 Rxc4 12.Rb3+ Ka6 13.Ra3+ Ra4 14.Rxa4+ Qxa4 15.Qg6+ Rc6 16.Qd3+ Kb6 17.Qb1+ Qb5 18.Qxb5+ Kxb5-+
I somehow guess that the line given with 2.Qe3+ and 3. Rb4 (threatening Qa3) is the bad one. Because black can give up his by …Qb6 and the play continues. I don’t see any such possibility for black to defend after the other line 2.Qe7+ 3.Rb3. For example 3…Qb6 is mate as Wayne from Canada pointed out. Simple but tricky.
How about the simple Rd4 threatening Ra4?
1. Rd4 Nb6 2. Qd3 Rhc8 3. Rdb4 (3. Rd6 Qc4 {saves the day for black …}) 3… g5 4. Rxb6 Qxb6 5. Rxb6 Kxb6 6. hxg5 hxg5 7. Qe3+ Kc6 8. a3 {White just picks up the pawns and wins!} *
*Kind of an easy win …
D.K.
I think lambent is right. If instead 1.(Rdd5) QxR then 2. Qe3+ followed by 3.Qb6+#
Susan, I enjoy the puzzles you post, but solving them tends to be fairly straightforward. Could you also give a little more detail about the game conditions (e.g., Elista 2006, game 10), so we can look up the games on chessbase.com to see how the players ended up in the given position? I’m sure I’m not the only one who would find this helpful.
Thanks!
1. Rxd5! exd5
2. Qe7+ Ka6
3. Rb3 Qb6
4. Rxb6+ Kxb6
5. Qd6+ Ka7
6. Qxd5+-
Re request for details of the game:-
http://www.chessgames.com/perl/chessgame?gid=1252428
Dortmund Sparkassen Chess Meeting 2002 French Defense: Classical. Burn Variation
25Rdxd5 exd5 26Qe7+ Ka6 27Rb3 1-0
rd5 ed5 qe7 ka6 qb4 wins for white.