Troitsky 1927 presented by Andreas
White to move. How do you assess this position? How should White continue?
k3K3/2P4b/8/1p6/8/7B/8/1q6 w – – 0 1
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1. c8=Q+ Ka7
2. Qc7+ Ka8 (if Ka6 then Bc8++)
3. Bg2+ Be4
4. Qd8+ Ka7
5. Qe7+ and wins the Black Bishop
1. c8=Q+ Ka7
2. Qc7+ Ka8 (if Ka6 then Bc8++)
3. Bg2+ Be4
4. Qh7
A second fatal pin…
1. c8=Q+ Ka7
2. Qc7+ Ka8 (if Ka6 then Bc8++)
3. Bg2+ Be4
4. Qd8+ Ka7
5. Qe7+ and wins the Black Bishop
Maybe, but White still has work to do. Unfortunately he can’t capture the bishop with his queen, because he’ll be left with insufficient mating material.
Anon 1:50’s 4.Qh7! wins outright.
C8 = D + , Ka7
Dc7 + , Ka6
Bc8 #
Or
C8 = D + , Ka7
Dc7 + , Ka8
Bg2 #
Bigdad
1. c8=Q+ Ka7
2. Qc7+ Ka8 (if Ka6 then Bc8++)
3. Bg2+ Be4
4. Qh7
its importaint, that black cant cover the b7 square and has no check after
4…Kb8
5. Bxe4
The solution is :
1.c8Q+ Ka7 2.Qc7+ Ka8 3.Bg2+ Be4 4.Qh7!
[4.Qd8+?! Ka7 5.Qe7+ Kb6 6.Bxe4 Qc1 7.Qb7+ Ka5 very slight advantage for White]
4…Kb8 5.Bxe4+- (threatens Queen & mate)
Pharaoh