Group A
P. Leko – V. Anand |
|
| F. Caruana – L. Dominguez | |
| S. Tiviakov – S. Karjakin | |
| J. Smeets – V. Kramnik | |
| L. van Wely – A. Shirov | |
| N. Short – V. Ivanchuk | |
| H. Nakamura – M. Carlsen |
Group B
| T. Nyback – E. l’Ami | |
| A. Giri – E. Sutovsky | |
| D. Howell – Ni | |
| A. Muzychuk – D. Reinderman | |
| A. Naiditsch – L. Nisipeanu | |
| W. So – P. Harikrishna | |
| V. Akobian – P. Negi |
Group C
| M. Muzychuk – S. Swaminathan | |
| S. Kuipers – R. Swinkels | |
| Z. Peng – R. Robson | |
| B. Bok – A. Gupta | |
| D. Vocaturo – N. Grandelius | |
| S. Plukkel – K. Lie | |
| L. Chao – R. van Kampen |
Chess Daily News from Susan Polgar
Go Naka !!!
Win one for the USA. Go Naka!
Most likely a draw, I presume.
I wonder if it is an advantage for Naka to play the strongest player with the white pieces.
Also, with 13 rounds to play 7 players have 6 times white and the other 7 have 7 times white.
So, in case of equal points the ones with more black should be in front, shouldn’t they?
In case of equal points they share the place. Period. There are no artificial tiebreak criteria.
It has always been so, and it will always be so in Wijk aan Zee.
Gens una sumus