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… Bc5!
if:
Rxc Rd2+ wins
if:
Rc1 Rd1+ wins
But if white doesn’t cooperate, I don’t know 🙂
How about 1… Rc4
1Rc4 Rc8 or 1 … bxc
2Bc5 and win
Of course the strongest move is Rc4!, this is a simple one.
The connected pawns win easily against the remaining rook.
1. -, Bc5!? only gives black a smaller advantage.
After 2. Rxc2, Rd2+?? is a horrible blunder as white simply plays 3. Rxc5!
Correct would be playing 2. -, Rc4+ protecting the bishop.
After the forced 3. Rcf2 black can play Rb3 and wins at least a pawn.
If white does not take c2 but plays Kg2 instead black (again) has to find Rc4 with the same idea above.
Best regards
Jochen
1.Rc4 Rc1
2.Bc5 Kg2 (2…PxR 3.BxR+ KxR 4.b3 wins easily)
3.BxR KxR
4.a5! and white should wins easily since 5.Rc3…6.Rxb3 RxP 7.Ra3 and white’s a pawn is lost.
A Yurgis – Mikhail Botvinnik [A14]
Leningrad tt Leningrad tt, 1931
1.Nf3 Nf6 2.c4 c5 3.Nc3 b6 4.g3 Bb7 5.Bg2 d5 6.cxd5 Nxd5 7.0–0 e6 8.b3 Be7 9.Bb2 0–0 10.Nxd5 Bxd5 11.d3 Nd7 12.Qc2 Rc8 13.Rae1 b5 14.e4 Bb7 15.Nd2 Nb8 16.f4 Nc6 17.a3 Qd7 18.Nf3 Rfd8 19.Rd1 Ba6 20.Ba1 b4 21.a4 Nd4 22.Qb2 Bf6 23.e5 Be7 24.Nxd4 cxd4 25.Qe2 Rc5 26.Bb2 f5 27.h4 Rc3 28.Bxc3 dxc3 29.Qe3 Bxd3 30.Rf2 Qd4 31.Qxd4 Rxd4 32.Bf1 c2 33.Rc1 Bxf1 34.Rcxf1 Rc4! 35.bxc4
[35.Rc1 Bc5 36.Kf1 Bxf2 37.Kxf2 Rc3 38.Ke2 Kf7 39.Kd2 Rxg3 (Not 39…Rxb3?! 40.Rxc2 Rxg3 41.Rc7+ Kg6 42.Rxa7µ) 40.Kxc2 Rc3+–+]
35…Bc5 36.Kg2 Bxf2 37.Kxf2 b3 0–1
Pharaoh