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After looking at it for less than a minute, I don’t think Black can win after 1…Kg4 2. Ka2. I’m usually wrong about these, though.
Black needs to make White take at a1.
1. …..Kg4
2. Ka2 Kg3
3. Ka1 Kg2
4. Kb2 Kf2
5. Kc1 Ke1
And I don’t see how black can make progress towards a win.
I think black wins after Kg4 Ka2, Kg3 Kax1, Kxg2 Kb2, Kf2 Kc2, Ke2 and white lose their both pawns
There’s always a trick to these, though. Maybe if white goes after the bishop, black has time to get the g-pawn and gain the opposition on white and win the c-pawns.
… c4+ wins
h
Nice move by the black. Surely it win. I like the move.
Hello
1. …. , Kf4
2. Ka2 , Bc3
3. dxc3 , c4!!
4. dxc4 , d3 winning
Greetings from Spain
How about?
1) ….kg4
2)kc4 kg3
3)kxc5 kxg2
4)kc4 kf2
5)kb3 ke1
6)kc2 ke2
7)kc1 kxd3
8)kd1 bc3
9)dxc3 dxc2
0-1
Kf4 wins like Jose said
The sacrifice of the Bishop on c3 is crucial.
1…Kf4 is the solution. And now white has the choice between 2. Ka2 and 2. Kc2 (overlooked by all the intervenants)
2.Ka2 Bc3
3.dxc3 c4
4.Kb2 Ke3 (the true meaning behind 1…Kf4)
2.Kc2 Kg3
3.Kb1 Bc3
4.dxc3 Kxg2
This puzzle is a rotated study.
(Belikov, Shakhmaty v SSSR, 1967, 13)