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This might seem a bit loose, but let’s try:
1. dxc7 (clearing d6 for a knight fork)
1. … Qxd5
2. cxb8(Q) Qxc4
3. Qxe5+ fxe5
4. bxc4 Nc5
5. Bxg5 Be6
6. Bf1
White’s 2 extra pawns should be enough.
jcheyne
dxc7, if qxc7, qg8, kd7, bh3, kc6, qd5
dxc7 qxc7, qg8, ke7, nd5
dxc7, qxd5, cxb8Q, and the line given by jcheyne might be enough already