5RB1/6p1/7p/6kP/p7/1n1r2PK/2p2P2/8 w – – 0 1
White to move. How does White stop Black’s passed pawns? How should White proceed?
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White should find a mate before black queens.
1.f4+ Kxh5 2.Bf7+ g6 3.Rg8 and black can resign now.
White at least has a draw by:
1.Bh7 Kxh5 2.Bxd3 c1=Q 3.g4+ Kg5 4.Rf5+ Kg6 5.Rf8+ Kg5 6.Rf5+ and perpetual check.
1.f4+ Kxh5 2. Rf6
How about
1. f4+ Kxh5 2.Bf7+ g6 3.g4++
“Anonymous said…
How about
1. f4+ Kxh5 2.Bf7+ g6 3.g4++”
3. g4 is not possible as the pawn is pinned
I think 1. Bf5 and the king must move to the f-file, then 2. BxN+ and the pawn is won, too.
Brad Hoehne
Brad Hoehne
white: pawn f2 to f4
black: king g5 to h5
white: bishop g8 to f7
black: pawn g7 to g6
white: bishop f7 to c4
black: rook d3 to d2
white: pawn g3 to g4
1. Bh7 (threatens Rf5#)
1.. g6
2. Bxg6 Nd4
3. Bxd3 c1=Q
4. f4+ Kxh5
5. g4#
“1.f4+ Kxh5 2.Bf7+ g6 3.Rg8 and black can resign now.”
Why resigning when he simply can play Rd6?
“1.f4+ Kxh5 2. Rf6”
Very cute but what about 2. -, Rd7 defending g7?
“1. Bh7 (threatens Rf5#)
1.. g6
2. Bxg6 Nd4
3. Bxd3 c1=Q
4. f4+ Kxh5
5. g4#”
1. -, g6??
2. Bxg6 Nd4
3. f4#
There’s no need to play g6 and this is a very bad move.
The idea of playing Bxd3 to free the g pawn is nice (and probably works after 1. Bh7, Nd4). But how does white proceed after 1. Bh7, Kxh5 (like proposed by vince, too)?
I am not convinced of any of the posted “solutions” here (sorry emperor_ropi I didn’t comment on your try – take another closer look at the variation – are the black moves all forced or are there better ones perhaps?) and I don’t have one myself.
This one looks so easy but seems to be a hard one! Very nice!
I have to take a closer look tomorrow….
Greetings
Jochen
1.Bh7 Kxh5 2.Rf5+ (2.Bxd3? c1Q 3.g4+ Kg5 4.f4+ Qxf4) g5 3.f3
with the idea of g4++.
Greetings from Toronto
I thought 1.Bh7 threatening Rf5# would be the key move. There are interesting variations:
1.-Rd5 (most natural) 2.f4+ Kxh5 3.g4#;
1.-Nd4 2.Bxd3 c1Q 3.f4+ Kxh5 4.g4#;
1.-g6 2.Bxg6 doesn’t change a thing.
1.-Kxh5! is the only move.
a) 2.Bxd3 c1Q 3.g4+ Kg5 4.Rf5+ Kg6 is only good for a draw.
b) 2.Rf5+ g5
b1) 3.Rf6 g4+ 4.Kg2 Nd4 and black wins.
b2) 3.f3 Rxf3, black wins.
c) 2.f3 Nd4! 3.Bxd3 c1Q and white can win the queen (4.g4+ and 5.f4+), but again he loses the game.
Anyway, this is more interesting than the actual solutions – there are several with 1.f4+ Kxh5:
a) 2.Bf7+ g6 3.Rg8 Rd6 (else Bxg6#) 4.g4#;
b) 2.Bf7+ g6 3.Re8 Nd4 4.Re5+ Nf5 5.Rxf5#;
c) 2.Rf6 (pretty: gxf6 3.Bf7#) Rd7 3.g4#
Ouh, I oversaw the simple g4. Thank, wortwart, so half of my post above is irrelevant. Sorry!
ana(8:37)’s try with f3 isn’t good (like so many others aren’t) because of Rxf3.
With wortwart’s hint I consider 1. f4, Kxh5 3. Rf6!! as the most elegant solution.
Yes I agree 2.Rf6! is the nicest also because of the following side variation:
If black plays 2..g6 then white plays 3. Rf5+ , and now black doesn’t have 3.. Kg6 (because he played g6) and either 3..gf or 3.. g5 is followed by 4. Bf7x
Real nice one if we didn’t have all those other trivial mates (with Rg8 and Re8 as mentioned WortWart)