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1.Bb3 Kh1 forced
2.Kg3 h2 forced
3.Bd5+ checkmate
trick is to force king to move. white must deny black option of moving his pawn to b3. So, to start the bishop has to block:
1) Bb3, Kh1
2) Kg3, Ph2
3) Bd5#
ag
1.Bb3! Kh1 2.Kg3! h2 3.Bd4#.
I love probkems in which restricting all but one piece’s ability to move is the key.
1.Bb3 Kh1
2.Kg3 h2
3.Bd5#
too obvious
Bb3 Kh1
Kg3 h2
Bd5#
1. Bb3 Kh1
2. Kg3 h2
3. Bd5#
1. Bb3 Kh1
2. Kg3 h2
3. Bd5#
1.Bb3, Kh1
2.Kg3, h2
3.Bd5#
And that’s all she wrote!
isnt that quite simple
1.Bb3 Kh1
2.Kg3 h2
3.Bmates
Am i missing anything?
1. Bb3 Kh1 forced
2. Kg3 h2 forced
3. Bd5 #
1. Bb3 Kh1
2. Kg3 h2
3. Bd5#
1. Bb3 Kh1
2. Kg3 h2
3. Bd5++
1.Bb2-Kh1
2.Kg3-h2
3.Bd5#
White must force the Black king into the corner to deliver checkmate with the bishop. Thus 1 Bb3 forces Black to play 1…Kh8.
Then, 2 Kg3 again forces the only legal move 2…h2 and White then mates with 3 Bd5. It is easier to solve the problem by visualizing, imagining the mate on h1, and understanding how to force “box moves” (one legal move only) to bring about mate, then it is to calculate many different lines like a computer would.
-Justin Daniel
1)Bb3 Kh1
2)Kg3 h2
3)Bd5#
1 Bb3 Kh1
2 Kg3 h2
3 Bd5#
1.Bb3 Kh1
2.Kg3 h2
3.Bd5#
1. Bb3, Kh1 2. Kg3, h2 3. Bd4#
Seems fairly straightforward and there are no variations because every Black move is forced.
Bb3 Kh1
Kg3 h2
Bd5 #
1. Bb3 Kh1
2. Kg3 h2
3. Bd5#
Easy
1. Bb3 Kh1 2. Kg3 h2 3. Bd5#
1.Lb3 Kh1 2.Kg3 h2 3.Ld5
1. Bb3, Kh1 2. Kg3, h2 3. Bd5#
Must have been pretty easy, got it pretty fast without a computer and I’m nothing special.
Very amusing repeated use of blocking blacks potential moves:
1. Bb3 Kh1 (only legal move)
2. Kg3 h2 (only legal move)
3. Bd5#