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1. Re8+ Rxe8 2. Rxe8+ Rxe8 3. f7+ b2 4. fxe8 = Q+ Kg7 5. Bxb2+ (then if Nxb2 it’s followed by 6. Qe5+ recovering the piece with winning advantage).
Spend the rooks on checks on e8, then f7+ followed by fxe8(Q), and White will win.
Trade rooks then push the pawn for discover-check, Right?
f7
and there is no defence
against rook and bishop
double check
It is mate
1. Re8+ Rxe8 2. f7+ b2 3. Rxe8+ Rxe8 4. fxe8Q+ Kg7 5. Bxb2+ Nxb2 6. Qe5+ Kh6 7. Qxb2 1-0
1.Re8+Rxe8
2.Rxe8+Rxe8
3.f7+Bd4
4.Bxd4+Ne5
5.Bxe5+Rxe5
6.f8=Q#
f7
1. Re8 Rxe8
2. Rxe8 Rxe8
3. f7+
Easy or i’m in good shape this morning.
Re8+
Rxe8
f7+
#
Re8 & Re8 + discovered ch wins
We are getting easy problems
1. Re8+ Rxe8
2. Rxe8+ Rxe8
3. f7+ b2
4. Bxb2+ Nxb2 (Ne5 Bxe5 Rxe5 f8=Q#)
5. fxe8=Q+ Kg7
6. Qe5+ Kh6
7. Qxb2
Up with Q+1p vs. B+3p.
1. Re8+!! Rxe8
2. Rxe8+! Rxe8
3. f7+ b2
4. fxe8=Q+ 1-0
1. Re8+ Rxe8
2. f7++
f7
There is no defence against
mate. If pawn b2 then f7 pawn
queens with the help of rooks
Actually, I think f7+ works as move 2# also, even though most of us wanted it to be move 3#.
How can black deviate from:
1. Re8+ Rxe8
2. f7+ g2
3. Bxg2 Nxg2
4. Rxe8+ etc.
I looked at:
2. … Ne5
3. Rxe5!
and now the discovered threat looks overwhelming.
However starting with 2 rook checks and playing 3. f7+ was clearer and easier to calculate…