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1. Qd8
Qe6 treatening to take the two rooks and allowing to push c8.
Black cannot take the queen because of c8:Q+ and black are checkmated.
The move Rfe7 lost also because of QxR
1. Qe6 Rff8
2. Qd7 Rg8
3. Qe7 Rdf8
Then what?
Sorry wrong notations!
1. Qe6 Rff8
2. Qe7 Rg8
3. Qf7 Rdf8
Then what?
1. Qe6 Rff8
2. Qd7 Rg7
3. Qd6 Ref8
4. c8Q
Qe6 Rff8
c8:Q RxQ
Qe7
and black cannot protect f6 and g7
but if you play
1. Qe6 Rff8
2. Qd7 Rg7
3. Qd6 a1:Q -+
qe6,rff8, c8q, rxc8, qe7, rg8, qf6
1. Qd8 Rff8
2. Qd7
And there is no defense against Qg7 Mate (even after giving away the 2 rooks)
1. Qe6 Rff8
2. Qd7
and black wins.
2……Rg7
3. Qd6 a1:Q -+
Qe6 Rff8
c8Q Rxc8
Qe7!!!
and simple mate.
You’re right but answer was already given….
1-Qd8 Rff8
2-QXR following by c8=Q+ and winning the rook
What about Qc6?
1. Qc6 Ref8
2. C8=Q
Qe6!! if Rxe6 then c8=Q wins and
if Qe6 Bxd5
Qxe8+ Rf8
Qxf8 Bg8
Qg7#
Most importantly, white should take off that silly thinking cap. It looks just ridiculous.
And then, play 1 Qe6 Rf8 2 c8.