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Rd7!
Petrotal
Yes, Rd7. Black has a back rank mate problem.
but after Rd7….
Qxr
QxQ rxr and end up with 2 rooks vs queen which is not too bad for black
wonder if there is something better?
If (after Rd7 Qxd7) QxQ RxR then QxN leaves White with Q+B versus R+R.
Also, I think 1.Rd7 Ne5 is met by 2.Rxe5.
Rd7
The game actually continued 25.Rd7 Nh6, and now Schussler found another good move.
1.Rd7 Nh6
2.Qxg7+ Kxg7
3.Rxb7 Rxb7
4.Rxe8 with a winning position
Is it how the game continued?
No, I think
1. Rd7 Nh6
2. R1xe7 Nxg4+
3. fxg4 Qb8
4. Rxg7 Qf4
5. Rxh7+ Kg8
6. Rdg7+ Kf8
7. Rf7+ Kg8
8. Rhg7+ Kh8
9. Bxf6
seals victory most convincingly.
I have to admit another line is:
1. Rd7 Nh6
2. R1xe7 Rxe7
3. Rd8+ Ng8
4. Bxf6
so it might be a matter of taste after all when it comes to 2. R1xe7 and 2.Qxg7+ 🙂
1.Rd7 Nh6
2.Qxg7+ Kxg7
3.Rxb7 Rxb7
4.Rxe8 with a winning position
Is it how the game continued?
We have a winner!
1. Rd7 Nh6
2. R1xe7 Nxg4+
3. fxg4 Qb8
4. Rxg7 Qf4
This is a check; the rest of this line is illegal. 5.Kg1 is forced, and Black mates with 5…Re1#.
1. Rd7 Nh6
2. R1xe7 Rxe7
You had the right idea with 2…Nxg4+, which wins.