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1. Rxh2! Ng3 (only move against the threat Rh1+ Kxh1 Qxf2 … Rh8#)
2. Rxg2+! Kxg2 (only)
3. Ne3+ Kg3
4. Nxc2
Up with queen + 3 pawns vs. rook should be desicive enough.
1. … Ne3 (Bxe3, 2. Qxc2)
2. Qxc5 Rd1+
3. Rf1 Rxf1#
greets, jan
The White queen for a rook and a decisive advantage
1…Ne3 2.Qd2
(2.Bxe3 Qxc2)
(2.Qxc5 Rd1+ 3.Rf1 Rxf1#)
(2.Qb2 Rd1+ 3.Rf1 Rxf1#)
2…Rxd2 3.Bxd2
I would say
… Rxh2
threatening to double the rooks and deliver mate in h1.
Kxh2 Qxf2 with Rh8# coming.
Not sure that it is forced, but it seems winning.
Since no comments posted yet let me have a stab at:
1. Rh2 threat Rh1+ followed by Qxf2
and Rh8+ mating.
If 1….Kf1 Ne6+!
If 2….Bxe6 Qxc2
Anywhere near?
0-0-0
-0-0-
Rxh2 – bc4
…
I think Se3! is more forced.
It seems to me that both Ne3 and Rxh2 should be a quick win here.
I may agree that Ne3 is the quickest way to win, when you see it.
I didn’t see this move because I saw Rxh2 first…
Interesting puzzle, but wouldn’t it be better to also make the board positions available in algebraic notation?