This is your fun Thanksgiving teaser 🙂 Don’t pay attention to the diagram above. It is just a random picture.
Place 8 Queens on the board where they do not connect with each other. To win the game, you must place all 8 Queens on the board! (If you are using a set and board to set it up at home, use 8 pawns to represent 8 Queens)
Example: Queens on a3, b1, c4… As you can see, the Queens are not connected to each other.
Have fun! 🙂 
Chess Daily News from Susan Polgar
Wow, this was rather difficult. I almost thought it to be impossible, when I finally found the solution.
One solution is to put the queens on: g1, e2, c3, a4, f5, h6, b7, d8.
By the way: you have a very interesting blog. Thanks to Chessbase! (They had a link to your blog on their web-site, else I probably would never have found your blog)
For the mathematically inclined: see if you can count how many different solutions there are to this problem.
This one was super easy. I got it right away. well I am Math inclined.
there are 8 queens and 8 columns and 8 rows. nothing can share the column or row. so simply go
a1, b3, c5, d7, then back to e2, f4, g6, and everything is good so far. one to go. that would have to be h8. but that shares the diagonal with a1. so drop the queen down to h1 which is blocked by the king on e1.
Voila. solution.
this is my first solution so I feel very grateful and thank full on thanksgiving.
Happy Thanksgiving everyone.
Dont eat too much. I will do it for you. LOL.
Tommy, the King does not count. You have to do 8 queens without the King. As Susan said, the diagram is just a random pic. The idea is to put 8 queens without any other pieces without connecting.
Happy Thanksgiving to you!
a7, b1, c3, d8, e6, f4, g2, h5
is one of many possible solutions. No using other pieces to block!
If you use Google you can find lots of information about the so-called “8 Queens” problem (and other related problems with other pieces…)
One I like is this:
http://spaz.ca/aaron/SCS/queens/
Kerry Liles
Thanks Kerry!
Best wishes,
Susan Polgar
http://www.PolgarChess.com
http://www.SusanPolgar.com
In that diagram I’d resign.
I think what susan meant is that the kings are in a random position.
if she wanted the kings removed from the board she would have said to remove the kings from the board. she would have said to use a blank board.
but she did not say that. she said the kings were in random positon. so there is a different solution if the kings are on different random squares.
come on susan. this is going to be my first win. dont take it away from me. it is thanksgiving and I am grateful for getting my first puzzle correct.
Tommy
OK, you got it 🙂 Happy Thanksgiving! When you have a chance next week, try to find one without any King on the board.
Best wishes,
Susan Polgar
http://www.PolgarChess.com
http://www.SusanPolgar.com
OK here
http://www.math.utah.edu/~alfeld/queens/queens.html
there are 12 solutions to the problem if there are no kings on the board. but we have 2 kings on the board.
sorry but the problem susan presented was different than what is on the internet.
tommy