White to move and checkmate in 4.
r4r2/3p1pk1/1p2bq1p/3n3Q/4R2P/p2B4/1B4P1/7K w – – 0 1
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1.Rxe6 dxe
2.Qg4 Kh8
3.Qe4 (any)
4.Qh7#
1.Rg4+ Bxg4 (1…Kh8 2.Qxh6#) 2.Qxg4+ Kh8 3.Qf5 and 4.Qh7#
1.Rg4+ Bxg4
(Kh8 2. Dh6+ Kg8 3.Dh7++)
2.Dxg4+ Kh8
3.De4!! any move
4.JAQUE MATE Dh7++
Nice problem
There is a trap with
1.Rxe6?? because Rf8-d8!! And there is not mate in 4
1.Rxe6? fxRe6?
2.Qg6+ Kh8
3.Kh7++
1.Rxe6? dxRe6?
2.Dg4+ Kh8
3.De4 any move and
4.Dh7++
This is why is best check in g4, Rg4 is forced.
First I was looking at Qxh6+ trying to get the king out but if the dark squared bishop moves the queen is free so that doesn’t hold much promise.
Qg4+ Bxg4 Rxg4+ Kh8 the king is on it’s last square. Bxf6+ would be an awesome finish were it not for that stupid knight.
But we can sac the rook too, Rg4+ Bxg4 Qxg4+ Kh8 Qf5 going on the light squares and mate can’t be stopped.
1. Rg4+ Bxg4 (1. … Kh8 2. Qxh6#)
2. Qxg4+ Kh8
3. Qf5 any
4. Qh7#
Dear Andrew: the problem with 1.Rxe6 is 1. … axb2
1. Rxe6 axb2
It looks as if the best that White can do after that is:
2. Qg4+ Qg5
3. hxg5 dxe6
4. gxh6+ Kf6
5. Qg7+ Ke7
6. Qxb2 f6
and it is doubtful that White can win. And there is certainly no mate in 4 after 1. Rxe6.
1. Rg4+ Bxg4
2. Qxg4+ Kh8
3. Qf5 (any)
4. Qh7#
1.Rg4+ Bxg4 (1…Kh8 2.Qxh6#)
2.Qxg4+ Kh8
3.Qf5 any
4.Qh7#
Andrew,
1. Re6 ab2 looks ok for black- it might even be winning for black, but is certainly not a mate in 4 in white’s favor.
I would see, first, if I could sacrifice at h6:
1. Qh6 Kh6
Here, Kg8 loses, too: [1. …Kg8 2.Rg4 Bg4 (or 2. …Qg6/5 3.Qh8#) 3.Qh7#]. Continuing:
2. Bc1
I don’t see 2.Bf6 leading anywhere. Only 2.Bc1 seems to offer any semblance of an attack (not that I am seeing that, now that I am thinking about it). Continuing:
2. …..Kg7
And I don’t really need to think about this any more- this line definitely isn’t it. So, let’s try the other obvious sacrifice move:
1. Rg4 Bg4 (Kh8 2.Qh6#)
2. Qg4 Kh8
This is pretty!
3. Qf5!
Here, Qe4 works, too, but thumbing the nose at the pinned black queen has a bit more panache. There is no way to prevent Qh7# on the next move.
1. Rg4+! Bxg4
2. Qxg4+ Kh8
3. Qf5! and mate next move.
(1) Rg4+ Bxg4
If (1)… Kh8
(2)Qxh6 mate
(2) Qxg4+ Kh8
(3) Qe4 Any move
(4) Qh7 mate.
1.Rg4+ Bxg4
2.Qxg4+ Kh8
3.Qf5 Qxb2
4.Qh7#
– High skills of MR KO (Malaysian)
I think sac Rg4 prob gets job done.
I think sac’ing the Rg4 prob gets the job done
1. Rg4+ Bxg4 (if Kh8 then Qxh6#)
2. Qxg4+ Kh8 (forced)
3. Qe4 (any move)
4. Qh7#
i think, it must be
1. Rg4+ Bxg4
2. Qxg4+ Kh8
3. Qf5 any
4. Qh7#
greets, jan
A Q mate on h7 looks desirable (black has no piece to protect it).
It needs to start with a rook move, and Rxe6 isn’t enforcing enough, so more natural looks:
1. Rg4+ Bxg4 (Kh8 Qxh6#)
2. Qxg4+ Kh8
3. Qe4/f5 any
4. Qh7#
Almost the same as Andrew’s suggestion, but killing the bishop with check is better than without check.
1. Rg4+ Bxg4 (Kh8, Qxh6#)
2. Qxg4+ Kh8
3. Qe4 any
4. Qh7#
1. Rg4+ Kh8 (1… Bxg4 2. Qxg4+ Kh8 3. Qe4) 2. Bxf6+ Nxf6 3. Qxh6+ *
Rg4+,BXg4(Kh1 loses to Bxf6+,NXf6;QXh6#); QXg4+,Kh1; Qf5,Qg7 (all other moves are equivalent and lose to Qh7#);Qh7#
1.Rg4+…
a)1…Kh8 2.Qxh5#
b)1…Bxg4 2.Qxg4+ Kh8 3.Qf5!… (3…whatever ) 4.Qh7#
1.Rg4+ Bxg4
2.Qxg4+ Kh8
3.Qf5 and the mate is inevitable.
1Rg4+ Bxg4
(if 1… Kh82 2Qxh6#)
2Qxg4+ Kh8
3Qe4 and
4Qh7#
Um…I wont even look at this position….white has too much good funk going on…its too easy
Yea Thanks ppl.. I see my mistake now..
looks like 1.Rg4 is the only solution xD
I shall be more careful next time =)