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1. … Rd1
2. Rxd1 Qxc6
1…… Rd1+
2.Kh2 Qf4+
3.Kg2 Rxc1
Td1+; 2- Rh2, Th1+ ; 3-Rg3, Dd3+…….a) 4-Df3, DxD+; 5-RxD, TxT …..b) 4-Rg2,Dxh3++ ….c) 5-Rh4, Dxh3++
All these variations are good.but what about d)4.f3 ?
Replace the white pawn at g4 by one at g3 ; then you have to modify the tactic.
1…… Rd1+
2.Kh2 Rh1+
3.Kg3 Rg1+
4.Kh4 g5+
5.Kh5 Qg6++
5. … Qg6# is not possible because of pawn f6
Also,
3. … Rg1+
4. Kh2 yields nothing
fajac,
You seem to have confused (you are not to be blamed because it is usually white to play and win) about the approach to g6. It is black Q who has to go to g6 and P at f6 precisely makes it possible since it blocks white Q’s approach to g6.
5. … Qg6# is not possible because of pawn f6
But, it is possible!
Also,
3. … Rg1+
4. Kh2 yields nothing
Fair enough, but:
3. … Rh1+
4. Kg3 Qe5+
wins
Anup’s and my variations together suffice for this puzzle. there can be two variants of the puzzle.
(1) Remove the h3 pawn and place it at h2. Anup’s solution is the only solution.
(2) Remove g4 pawn and place it at g3. Now
1….. Rd1+
2.Kh2 Rh1+
3.Rxh1 is now forced and black gets the Q.