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Ba3+ Qxa3 Qc7++
Be5+ looks good for white.
Be5? Rxe5
Better:
Ba3+ QxB
Qc6++
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1. Ba3+ (a) QxB
2. Qc7#
1. … (b) Qc5 (Qb4, 2. BxQ#)
2. BxQ+ Kc6
3. Be7+ K any
4. BxR 1-0
Mark
1.) Ba3+ [If 1.) … Qxa3 2.)Qc7# – If 1.) … Qb4 2.)Bxb4# – If 1.) … Qc5 2.) Bxc5+]
Ba3!!
1.Ba3+ (deviating the black queen) Qxa3 2.Qc7#
Have a nice weekend!
No, (I did wonder a long while(well short really) on Be5 Rxe5 fxe5, but that didn’t seem promising or inspiring.)
Instead 1.Ba3+ Qxa3 2. Qc7# is checkmate already :).
1.Ba3+ Qxa3 2.Qc7#
Ba3+ deflects the black queen away from protecting the c7 square, so that white may play Qc7++.
I would prefer Pf4f5 forcing the White rook to either e4 or e8 allowing the queen to directly threaten the black king by taking out h6 pawn.The king will have to retreat to the 7th row and after that, mate is possible by a number of combination of checks while the White defence remains intact.The other possible move Be5 would force Black to take out the Bishop and leave black queen free to take out White rook with Qd2+ should WHite miss one check.
1. Ba3+ Q:a3 2. Q:c7# seems like the plan.
Ba3+
Ba3+
White should start with Ba3+.
Then if black plays 1)…Qa3, next Qc7#
So black has to play 1)…Qc5.
Then 2)Bc5+ and now it’s a easy win for white.
-Saon
1: Ba3+, Qxa3
2: Qc7++
Ba3 wins the queen! 1.Ba3!!Qa3?? 2. Qc7++ so queen must interpose since there is no other way to get out of check. So 1.Ba3!!Qc5 2.Bc5 Kc6 that is all I’m sure of. It seems like there should be a forced mate but I just don’t see it. I think probably 3. Ba7+Kb5 4.Qd3+Ka5 and I can’t see the rest 5.Qc3 maybe. there must be a forced mate in there.
sac Ba3+, then Qc7++
I wasted a moment looking at b4, but Ba3+ is pretty obvious
Just plugged it into Winboard. I knew there had to be a forced mate. I could have found it if I would have been more patient and looked for the most forcing move on each individual move. A beautiful composition. Or is this from a real game? Either way it is beautiful.
Ba3+ QxB
Qc7++
1.Ba3+! Absolute deviation 1…Qxa3 2.Qc7 mate !
It’s funny that the Black Friday tactic consists in giving a large part of our pieces (already a rook down and now a bishop ) to pursuit one single beautiful aim (tracking the opponent’s king to death) while we normally rush in the stores eating and shopping which is not essential, to say the least 🙂 (something i must admit i wouldn’t abandon too soon ^^)
Well there is 1….Qc5 so that’s not that idealistic ^^ although of course such move shouldn’t be analyzed…
1. Qc7 would be mate were the Black queen not guarding c7, so 1. Ba3+ wins: 1. … Qc5 2. Bxc5+ Kc6 3. Bd4+ Bc4 4. Rxc4+ Kb5 5. Qxb7+ Rb6 6. Qxa7 and mate next (6. … Ra6 7. Qc5#; 6. … Rxd4 7. Qa4#; 6. … Ra8 7. Qxb6#).
Since this is Black Friday, however, let’s make it Black’s move and find the mate in 6: 1. … Qd2+ 2. Kh3 Bg2+ 3. Kg4 (3. Kxh4 Qf2+ 4. Kg4 Qf3+ 5. Kh4 Qh3#) Qe2+ 4. Kxh4 (4. Kf5 Be4#) Qf2+ 5. Kg4 Qf3+ 6. Kf5 Bh3#. True, that’s more of a king chase than a puzzle, but it’s timely for the holiday rush.
“Black Friday.” It’s what happens to your soul if you take part. 🙂
Stronger is 1.Ba3+
If 1…Qxa3 2.Qc7++
can it be as simple?
1. Ba3+ Qc5
2. Bxc5+ Kc6
and now grabbing either the pawn on e3 or the rook on d8. both should be winning. greets, jan
Ba3+ wins 😉
I like Ba3+ to deflect the queen from c7.
Ba3+
Why not just Ba3 ?
Ba3 is mate in two.
Ba3! forces Q@B then Qc7 mate….pretty simple one.
Ba3 seems to be winning because Qxa3 is met with Qc7#
Too simple: Ba3 and mate! I saw it in 5 sec.
Ba3 is mate in 2
1. Ba3 Qa3 (forced)
2. Qc7#
I think 1.Ba3 wins in all variations:
1.Ba3+ Qxa3?
2.Qc7#
1.Ba3+ Qb4
2.Bxb4#
1.Ba3+ Qc5
2.Bxc5+ Kc6
3.Bxa7+ Kb5(Kd6, 4.Qc7#)
4.Qd3+ Bc4
5.Qxc4 Ka5
6.Qa4#
4….Kb4
5.Qd4+ Ka3(Ka5 6.Qa4#)
6.Bc5+ Kxa2
7.Qa4+ Kb2
8.Qa3#
4….Ka5
5.Rc5+ Kb4
6.Qc3+ Ka3
7.Ra5#
5.Qd4+ Bc4
6.Rxc4+ Ka5,b5(Ka3,7.Ra4#)
7.Qc5 Ka6
8.Ra4#