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1. …Qb4+! 2. Qd4 (2. Kd3 Rd2#) f5+ 3. gxf5 gxf5+ and the Queen will fall.
Qb4!!!+
1…Qb4+ is devastating, but I’m not sure it can be called brilliant.
2. Qd4 f5+ 3. gf: gf:+ and White’s Q departs the premises.
Rc8
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1…Qb4+ which forces 2.Qd4
(2.Kd3 Rd2#)
Now the f pawn is unrestrained so after
2…f5+
3.gxf5 gxf5+
the white king can no longer protect the queen.
4.Kxf5 Qxd4 leaving both the rook and bishop en prise which forces
5.Re4 (5.Re8+ Kf7 still attacking both pieces)
At this point as a human player (I am sure that a computer would go for a more complex variation with a bigger evaluation)I would sacrifice the queen to go into the endgame a clear rook up with
5…Qxe5+
6.Kf4 Qxe4+
7.Kxe4 Rxg2
…Qg5+
Qd5 Qxd5
Kxd5 Rxb7
winning a bishop in the exchange.
1…Qb4+
If 2.Kd3,
2…Rd2#
If 2.Qd4,
2…f5+
3.gxf5 gxf5+ (White’s other king moves don’t help)
4.Kxf5 Qxd4
Which leaves black ahead with a queen to a bishop and pawn.
1…Qb4+ 2.Qd4
(2.Kd3 Rd2#)
2…f5+ 3.gxf5 gxf5+ 4.Kxf5 Qxd4
1…Qb4+
2.Qd4 f5+
1. … Qb4+!
2. Qd4
2. Kd3 Rd2#
2. … f5+! and White’s king must devorce his queen or else will get mated:
3. Kd3 Rd2#
I notice that the end game can be entered with:
1. … Qb4
2. Qd4 (Kd3? Rd2#) Qxd4
3. Kxd4 Rxg2
I like black’s pawns and rook better here. Seems like black has the initiative. E.g.:
4. a3 gxh5
5. gxh5 Rh2
6. Rc3 Rxh5
7. Rc6 Re5+
8. Kd4 h4
In a practical game, I would certainly enter the endgame with Qb4+ and Q exchange, since I feel this moves initiative from white to black and black looks better to me.
I find it difficult though to call this “brilliant tactic”, it’s more like “stright forward”….
Other ideas look more farfetched to me (Qxg2? is obviously wrong). If there is a combination, i have missed it.
1.…Qb4
White has two responses: 1. Kd3 is hardly appealing as Black’s retort is …Rd2#, so White is forced to place their Queen in a precarious position.
1 …Qb4+
2.Qd4 f5+
3.gxf5 gxf5+
4.Kxf5 Qxd4
1. ….Qb4+!
2. Qd4.f5+!
3. gxf5.gxf5+
A4.Kd3.Qd2#
B4.Kf4.Qxd4+ netting the queen and winning easily
C4.Kxf5.Qxd4 netting the queen and winning easily. 5. Rd8+ is of no avail due to Kf7.
Harry
Just to add to my solution…
1. ….Qb4!
If 2.Kd3.Rd2#
Harry
1. … Qb4+
2. Qd4 (Kd3 is met with Rd2++) f5+
3. Kf4 Qxd4 wins the queen.
…Qb4+
Qd4 f5+
gxf5 gxf5+
Kxf5 Qxd4
1. … Qg5+ (2. Kd6, Rd7#)
2. Qe5 c4+
3. bxc4 bxc4+ (4. Kd6, Rd7#)
4. Kc5/xc4 Qxe5
Greets, Jan
So here was a combination.
I missed the rather elementary f5+.