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perpertual check with the light-square bishop. Bd3+, Bc4+.
1 .. Be6+
2 Kd6? Rd3+ (2 Ke4? Re3#)
3 Nd4 Rxd4+
4 Kc6 Kxe7 is winning, therefore the best reply to Be6+ would be
2 Rxe6 fxe6
3 Kxe6 and white is probably even better
1 .. Bc5! forces to move the rook with the mate as a result or to lose the rook.
1… Be6+
Line 1
2 Ke4 RxN
Line 2
2 Kd6 Bc5+
2 Kc7 BxR
(Knight is pinned)
Line 3
2 RxB fxR+
3 Kd6 (3 Kxe6 RxN)
… Bc5+
4 Kd7 Kf7
(e pawn is blocked)
Line 1 loses White a Knight, line 2
a Rook, Line 3 forces White to trade Rook for Bishop.
Mark
In my opinion, after
1. … Be6+
2. Rxe6 fxe6+
3. Kxe6
white is still winning, with three passed pawns for the exchange. (And yes the bishop and knight are protected by pawn and bishop respectively.
Yea, simply 1… Bc5 does it, if 2. Rf2 then 2…. Be6+ Ke4 3. Re3#, and with an extra rook for black it is white who has to search for a draw, despite his two connected passed pawns.
1… Rxc6
Bc5 is crushing
The FEN code below the diagram makes a completely different position from that on the diagram.