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rg1 wins
1. Bxe5+ Rxe5
(1… dxe5 also is met with the same continuation.)
2. Qf6+ Kg8
3. Rg1+ Kf8
4. Qxd6+ Re7
(4… Ke8 5. Rg8#)
5. Qh6+ Ke8
6. Rg8+ Kd7
7. Qc6#
1, Bxe5+
if 1… Rxe5
2. Qf6+ Kg8
3. Rg1+ Kf8
3. Qd6+ Re7
4. Qh6+ Ke8
5. Rg8+ Kd7
6. Qc6#
if 1… dxe5
2. Qf6+ Kg8
3. Rg1+ Kf8
4. Qd6+ Re7
5. Qh6+ Ke8
6. Rg8+ Kd7
7. Qc6#
This looks like deja vu all over again. Didn’t you have this problem before? White mates with 1.Bxe5+ Rxe5 (or 1…dxe5) 2.Qf6+ Kg8 3.Rg1+ Kf8 4.Qxd6+! Re7 (4…Ke8 5.Rg8#) 5.Qh6+ Ke8 6.Rg8+ Kd7 7.Qc6#
We had this mating sequence once before. And I think we may even have had it at least twice. 😉
The positions before were only slightly differing in the rest of the position. This bishop, bishop, queen, rook, pawn setup is just too obvious. :-))
The main line ends with 7. Qc6#. 🙂
Is this pattern recognition as it should be!?
Best wishes from Germany
Jochen
Easy. Mate in 7, with checks all the way.
Game over
1. Bxe5+ Rxe5 (or dxe5)
2. Qf6+ Kg8
3. Rg1+ Kf8
4. Qxd6+ Re7
5. Qh6+ Ke8
6. Rg8+ Kd7
7. Qc6#
I came up with: 1.Bxe5+ dxe5 2.Qf6+ Kg8 3.Rg1+ Kf8 4.Qd6+ Re7 5.Qh6+ Ke8 6.Rg8+ Kd7 7.Qc6#
‘How should White proceed?’
I haven’t the faintest idea!
Looked simple. 1. Bxe5+!! wins it for white with a forced mate in 7. We can discount 1… f6 as 2. Bxf6 is mate. So what we have is: 1… dxe5 or Rxe5. In both cases the continuation is forced and the same.
2. Qf6+ Kg8
3. Rg1+ Kf8
4. Qd6+ (or Qxd6+) Re7
5. Qh6+ Ke8
6. Rg8+ Kd7
7. Qc6#
There is a minor variation when black plays 1… Rxe5, which is at blacks 4th move: 4… Ke8 5. Rg8#.
I thought, you posted it some time ago.
And I found this:
http://susanpolgar.blogspot.com/2009/10/checkmate-in-7.html
Nearly the same.