In the event of a tie:
- Two Players: The tie will be broken with a two-game rapid match (G/15 plus 5 second increment). If the contest is still undecided, the match will be decided by an Armageddon Game.
- Three players: If there are three Players tied for first, the two Players with the lowest tie-breaks will contest an Armageddon Game. The winner of this game will face the player with the highest tie-breaks as described above (“Two Players”).
Round 8 results
- IM Chandra, Akshat vs FM Shen, Arthur [1-0]
- IM Xiong, Jeffery vs FM Liang, Awonder [1-0]
- IM Liou, Yian vs Brattain, Mika [1/2-1/2]
- FM Li, Ruifeng vs Han, Curran [1-0]
- IM Harmon-Vellotti, Luke vsFM Bodek, Michael [0-1]
Standings after 8 rounds
Rk | Name | Rating | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | Score |
---|---|---|---|---|---|---|---|---|---|---|---|---|---|
1 | IM Chandra, Akshat | 2589 * | x | ½ | 1 | ½ | ½ | ½ | 1 | 1 | 1 | 6.0 | |
2 | IM Xiong, Jeffery | 2621 * | ½ | x | 1 | ½ | ½ | 1 | ½ | 1 | ½ | 5.5 | |
3 | FM Shen, Arthur | 2505 * | 0 | 0 | x | 1 | 1 | 0 | 1 | 1 | 1 | 5.0 | |
4 | FM Li, Ruifeng | 2488 * | ½ | ½ | 0 | x | ½ | 1 | ½ | ½ | 1 | 4.5 | |
5 | FM Bodek, Michael H | 2528 * | ½ | ½ | 0 | ½ | x | 1 | 0 | ½ | 1 | 4.0 | |
6 | IM Liou, Yian | 2501 * | ½ | 0 | 1 | 0 | x | ½ | ½ | 1 | ½ | 4.0 | |
7 | IM Harmon-Vellotti, Luke | 2545 * | 0 | ½ | ½ | 0 | ½ | x | 1 | ½ | ½ | 3.5 | |
8 | FM Liang, Awonder | 2483 * | 0 | 0 | ½ | 1 | ½ | 0 | x | ½ | 1 | 3.5 | |
9 | Brattain, Mika A | 2452 * | 0 | ½ | 0 | ½ | 0 | ½ | ½ | x | ½ | 2.5 | |
10 | Han, Curran R | 2211 * | 0 | 0 | 0 | 0 | ½ | ½ | 0 | ½ | x | 1.5 |
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