so the answer is 1.RXh7+ KXh7 2.Qe7+ Kh8 3.QXf8+ Kh7 4.Qg8+ Kh6 5.Qh8+ Kg5 6.f4+ Kf5 7.QXh5+ Kf6 8.Rf7# and yes its still bryce, and im sating my name so i can sho my dad when he gets home that it was me to solve the prolem…LOL
If 2…Kh8 then 3.Qxf8+ Kh7(forced)4.Qg8+ Kh6(forced)5.Qh8+ Kg5(forced)6.f4+ Kg5(forced)7.Qf8#
If 2…Rf6 then 3.Qxf6+ with either 3…Kh8 then 4.Qg8# or 3…Kh6 4.Qf8+ with either 4…Kg5 5.f4# or 4…Kh7 5.Qg8+ Kh6(forced)6.Qh8+ Kg5(forced)7.f4+ Kg5(forced) 8. Qf8#
If 2…Kh6 then 3.Qxf8+ with either 3…Kg5 4.f4# or 3…Kh7 4.Qg8+ Kh6(forced)5.Qh8+ Kg5(forced)6.f4+ Kg5(forced)7. Qf8#
chessdoc is, as usual, dead on with his analysis, except for 6…Kg5 7…Kg5 and 6…Kg5 from his three lines are obviously supposed to be Kf5.
Bryce buddy – your line needs a little magic to resurrect that rook… i was unbelievably confused for a while there. Qxh5 is never possible due to gxh5; your ideas are perfect, though.
1.RXh7+ KXh7
2.Qe7+ Kh8
3.QXf8+ Kh7
4.Qg8+ Kh6
5.Qh8+ Kg5
6.f4+ Kf5
7.QXh5#…i think,im not sure…
ohh, and the names bryce
I for got 7….Kf6
8.Rf7#
so the answer is
1.RXh7+ KXh7
2.Qe7+ Kh8
3.QXf8+ Kh7
4.Qg8+ Kh6
5.Qh8+ Kg5
6.f4+ Kf5
7.QXh5+ Kf6
8.Rf7#
and yes its still bryce, and im sating my name so i can sho my dad when he gets home that it was me to solve the prolem…LOL
Rxh7+ kxh7
Qe7+ Kh6
Qxf8+ Kg5
Qf4#
Rocketboy on icc said
QUOTE
Rxh7+ kxh7
Qe7+ Kh6
Qxf8+ Kg5
Qf4#
/QUOTE
This doesn’t work because black can play 3. — Kh7 instead of Kg5
1. Rxh7+ Kxh7(forced)
2. Qe7+
If 2…Kh8
then 3.Qxf8+ Kh7(forced)4.Qg8+ Kh6(forced)5.Qh8+ Kg5(forced)6.f4+ Kg5(forced)7.Qf8#
If 2…Rf6
then 3.Qxf6+ with either
3…Kh8 then 4.Qg8#
or 3…Kh6 4.Qf8+ with either
4…Kg5 5.f4#
or 4…Kh7 5.Qg8+ Kh6(forced)6.Qh8+ Kg5(forced)7.f4+ Kg5(forced) 8. Qf8#
If 2…Kh6 then 3.Qxf8+
with either
3…Kg5 4.f4#
or 3…Kh7 4.Qg8+ Kh6(forced)5.Qh8+ Kg5(forced)6.f4+ Kg5(forced)7. Qf8#
chessdoc is, as usual, dead on with his analysis, except for 6…Kg5 7…Kg5 and 6…Kg5 from his three lines are obviously supposed to be Kf5.
Bryce buddy – your line needs a little magic to resurrect that rook… i was unbelievably confused for a while there. Qxh5 is never possible due to gxh5; your ideas are perfect, though.
You may try to solve the following, an exciting solution.
White plays and wins.
4n3/8/N6P/2P5/4K2B/pk6/7b/8 w – – 0 1
1.Rh7 Kh7 2.Qe7 Kh8 3.Qf8+ Kh7 4.Bg8+ Kh8 5.Be6+ Kh7 6.Qg8+ Kh6 7.Qh8+ Kg5 8.f4#
In Bryce’s variation what about
7.-gh5 after 7.Qh5
It’s obvious that folks are utilizing computers. Why cheat???
1.Rxh7+ is unanimous here.
another approach:
1. Rxh7+ Kxh7
2. Qe7+ Kh6
3. Qxf8+ Kh7
4. Bg8+ Kh6
5. Be6+ Kh7
6. Qg8+ Kh6
7. Qh8+ Kg5
8. h3+ Rxh3
9. Qxh3#