Unless I am missing something, Nh5 looks like the winner:
1. Nh5 h1(Q)?? 2. Be8!! Kf5 3. Ng3+ spears the young queen with a fork.
If,
1. Nh5 h1(Q)?? 2. Be8!! Kh6 3. Ng3 and black is toast since the twin threats of Nh1 and Nf5# can’t be stopped by any move the queen other than Qh4:
3. ……Qh4 4. Nf5+ Kg5 (only move) 5. Nh4 winning the queen for the knight.
The major line for black deviates at move #1
1. Nh5 Kh5 (any other move, Ng3) 2. Bc6 Kg4 (h1(Q) 3. g4+ wins) 3. g3 Kg3 (what else?) 4. h5 and it is over as black will need to go Kf2/Kg1 just to force the bishop sacrifice at h1 and the c-pawn marches to his destiny at c8.
1.Nh5!! h1=Q, (if 1… Kxh5, 2.g4+! and 3.Bc6 +-. If 1… h1=N!? defending g3 it’s interesting, but not sufficient, because the simple 2.Nf4 saves the white knight) 2.Be8+ Kh6, 3.Ng3!, attacking the queen and threatening mate with 4.Nf5. It is no defense. If 3… Qxh4, 4. Nf5+ winning the queen. Anyway, the queen is lost or will be mate.
I think 1. Nh5! solves the matter:
1. Nh5 Kxh5 2. g4+ and 3. Bc6
1. Nh5 h1=Q 2. Be8+ Kh6 (2…Kf5 3. Ng3+ wins) 3. Ng3 and the only queen move that prevents Nf5 mate is 3.Qxh4 and then 4.Nf5 wins the queen.
Unless I am missing something, Nh5 looks like the winner:
1. Nh5 h1(Q)??
2. Be8!! Kf5
3. Ng3+ spears the young queen with a fork.
If,
1. Nh5 h1(Q)??
2. Be8!! Kh6
3. Ng3 and black is toast since the twin threats of Nh1 and Nf5# can’t be stopped by any move the queen other than Qh4:
3. ……Qh4
4. Nf5+ Kg5 (only move)
5. Nh4 winning the queen for the knight.
The major line for black deviates at move #1
1. Nh5 Kh5 (any other move, Ng3)
2. Bc6 Kg4 (h1(Q) 3. g4+ wins)
3. g3 Kg3 (what else?)
4. h5 and it is over as black will need to go Kf2/Kg1 just to force the bishop sacrifice at h1 and the c-pawn marches to his destiny at c8.
1 Nh5.
If 1.. kh5 2g4.. 3 Bc6 wins easily.
so 1.. h1=8
2 Be8+ Kh6 (kf5 loses to ng3+)
3 ng3! threatens Nf5 #
3.. qh4
4 nf5 +.
Nice problem, but not Troitzky level.
Nh5!!
1. Nh5 h1(q)
2. Be8+ Kf5
3. Ng3 + wins the queen
“Of course” White wins with 1.Nh5!! (threatening Ng3) h1(Q) (1…Kxh5 2.g4+ and 3.Bc6) 2.Be8+ Kh6 3.Ng3!! with the dual threats of Nxh1 and Nf5#.
Frederick
1.Nh5 h1 = Q 2. Be8+ Nh6 3. Ng3 Qxh4 4. Nf5+ etc.
Nh5 h1=Q
Ng3 oh crap
1. Nh5 threatening Ng3 to stop the pawn,
if
1. … Kxh5
2. g4+ Kxg4
3. Bc6 stops the pawn and wins,
if
1. … h1=Q
2. Be8+
then if
2. … Kf5
3. Ng3+ (king moves)
4. Nxh1 wins,
else if
2. … Kh6
3. Ng3 Qxh4 (forced to prevent 4. Nf5#)
4. Nf5+ Kg5
5. Nxh4 wins.
Nh5 h1=Q (Kh5, g4 and B stops pawn)
Be8 Kh6
Ng3 R moves
Nf5 mate
Would take a few mins thought to find the correct N move on move 1. Looked at other promising ones first before seeing the N must cover g7
Nh5 h1=Q
Be8+ Kh6
Ng3 threatening both the queen and N55 mate
1.Nh5!! h1=Q, (if 1… Kxh5, 2.g4+! and 3.Bc6 +-. If 1… h1=N!? defending g3 it’s interesting, but not sufficient, because the simple 2.Nf4 saves the white knight)
2.Be8+ Kh6,
3.Ng3!, attacking the queen and threatening mate with 4.Nf5. It is no defense. If 3… Qxh4, 4. Nf5+ winning the queen. Anyway, the queen is lost or will be mate.
Kariston Pereira
Joinville – SC, Brazil.