White to move and win. Forget about Fritz because it will not find it. Have fun!
Chess Daily News from Susan Polgar
One for your brain
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White to move and win. Forget about Fritz because it will not find it. Have fun!
This is similiar to the position with three pawns on each side facing each other. The problem is you can’t get outside around the pawns right away. So the first step is seperate the pawns into islands. These techniques require giving up a pawn, but losing a pawn in the center is of no consequence because it can’t get past the king. Of course the black king can stop just one passer even on the flank, and so white needs a passer on each flank to be successful. So for example:
1. d5 cxd5
2. exd5 exd5
3. b5 axb5
4. cxb5 Ke7
5. g5 hxg5
6. f5 gxh4
7. fxg6 h3
8. g7 Kf7
9. a5 bxa5
10. b6
and white queens first and wins
Wonderful.
As Paris said, this is similar to 3 pawns facing each other, except we have two of them. So, here’s my solution which I think is nicer. The plan is to use the 3 vs 3 idea on queen side to create a passed c-pawn. If black lets white get a passed a-pawn instead, then his king can’t catch it. Once we have our passed c-pawn, black’s king moves to stop it, and then we do the 3 vs 3 trick on the king side to get a passed f-pawn. The king can’t stop both. So here’s my solution in moves:
1.b5! cxb5 (if 1…axb5 2.c5 dxc5 3.dxc5 bxc5 4.a5 and the pawn queens)
2.a5 bxa5
3.c5 dxc5
4.dxc5 Ke7 to stop the c-pawn
5.g5! fxg5
6.h5 gxh5
7.f5 exf5
8.exf5 and now black has to choose which pawn to stop, the c or the f.
if 8…a4 9.c6 Kd6 10.f6 a3 11.f7 a2 12.f8=Q CHECK! and the queen goes back to a3 and stops black queening.
In Paris’s solution, I think black’s first move is a mistake. He should take with the e-pawn instead, and then white can’t create a passed pawn on the queenside.
About Paris solution:
3…axb5 is a blunder and helps white victory.But 3…a5 is the good move.
About Jonathan O´Connor solution:
7…exf5 is a blunder too,with 7…a4 black is winning.
Sorry but I cannot find the answer, I check and check and I see just draw in every line.
The solution is :
1.d5! 1…exd5 (1…cxd5 2.a5 +-)2.exd5 cxd5 3.a5! bxa5 4.b5! axb5 5.cxb5 Ke7 (5…a4 6.b6+-) 6.b6 Kd7 7.b7 Kc7 (all forced) 8.g5! fxg5 9.h5! gxh5 10.f5!+-
DBI
The 1.d5 solution given seems wrong.
1.d5 exd
2.exd c5
seems to be a draw.
Neither does the 1.b5 solution work.
9…Kd6 “to stop the pawn” is not needed. 9…a3! and the new queen can stop the pawns and at least reach a Q ending with 6 extra pawns.
I agree with Paris and Jonathan O’connor. The idea of exchanging center pawns is a must so one can create a passed pawn. However, my additional idea is this: Have the white King take the distant opposition before any pawn moves. this will ensure that white will have it, if the need should arise, in the event that your dynamic breakthrough should fail; which I believe it will with proper play from black…but white will force the black King to retreat or to the side since the white King will have the direct opposition! That is my idea. My first move is 1.Kf2!
Ken, te solution is OK, if
1.d5 exd
2.exd c5
3.a5!
and wins easily
DBI
“Ken, te solution is OK, if
1.d5 exd
2.exd c5
3.a5!
and wins easily
DBI “
3.a5 bxa5
4.b5 axb5
5.cxb5 Ke7
6.b6 Kd7
7.g5! hxg5
8.f5 and the pawn goes through!
5k2/8/pppppppp/8/PPPPPPPP/8/8/5K2 w – – 0 1
I’m just wondering. If this can’t be solved by Fritz and a couple of other programs i’ll just tested – can it be solved with Botviniks old alghorithms – or do we have to go back to Larry Evans old paper and pencil methods?
I am not sure but the solution given seems to work except that black does not have to play into that. How about
1 d5 cxd5
2 cxd5 e5
and there is only 2 on queenside that can not force their way through and the black king is close to the other ones.
3 f5 g5
4 b5 a5 draw
This is simply not so easy. I do not see how to use the King moves to influence the pawns. Where would placement of the king before moving a pawn help.
If black follows me to a file. white on a3 black king on a7 then I can breakthough on f file. with g5. but if black stays on b7 then he gets back in time.
I have it working now.
1 g5 hxg5
2 f5 exf5
3 exf5 gxf5
4 h5 Kf7
5 h6 Kg6
6 d5 cxd5
7 a5 bxa5
8 b5 1-0
I feel good. I really believe I have the answer here. Susan we need to know who wins this one.
Sorry
I do get the passed pawn and first queen but black queens with check and has the better position. So my solution did not work.
I need to try b5 first instead of g5
1 b5 axb5
2 c5 dxc5
3 dxc5 Ke7
4 cxb6 Kd7
5 axb5 cxb5
6 e5 fxe5
7 h5 gxh5
8 g5 hxg5
9 fxg5
white king can stop the black pawns and white has 2 passed pawns far apart. Black has too much to do. If b4 then Ke2 has to stop the b pawn.
9 ….. b4
10 Ke2 b3
11 Kd1 b2
12 Kc2 h4
13 b7 Kc7
(13 1/2 b8Q Kxb8)
14 g6 h3
15 g7 h2
16 g8Q b1Q+
17 Kxb1 h1Q+
It does not work. one move too slow. I see I needed to do the same trick on black by queening my b pawn so I get a check when I queen on g file. so insert move.
move 13 1/2 changes things so that means move 16 is with check.
16 g8Q+ K moves
17 Qh8 stops the h pawn.
This finally wins for white.
lot of work.
Here is the cleaned up answer.
1 b5 axb5
2 c5 dxc5
3 dxc5 Ke7
4 cxb6 Kd7
5 axb5 cxb5
6 e5 fxe5
7 h5 gxh5
8 g5 hxg5
9 fxg5 b4
10 Ke2 b3
11 Kd1 b2
12 Kc2 h4
13 b7 Kc7
14 b8Q+ Kxb8
15 g6 h3
16 g7 h2
17 g8Q+ K moves
18 Qh7+ stops the h pawn. with easy win.
Here is professor Bob Hyatt’s
(or rather his program Crafty’s)
answer to this beautiful problem.
1. d5 cxd5
2. a5 bxa5
3. b5 axb5
4. cxb5 Ke7
5. b6 Kd7
6. exd5 exd5
7. g5 fxg5
8. b7 Kc7
9. h5 gxh5
10. f5 Kxb7
11. f6 g4
12. f7 h4
13. f8Q
Someone, please ask him how his forcefields works.
(i do not dare, because he hates me and my program)
http://www.cis.uab.edu/hyatt/hyatt.html
pelle your answer is based on the first move cxd5. what if black exd5 then that solution doesnt work because cxb5 will now be possible by black instead of Kf7.
wolverine
wolverine, i do not understand your Kf7?
was that a misspelling?
Anyway, after d5 exd5
the path to the 8:th rank
becomes much the same.
1. d5 exd5
2. exd5 cxd5
3. a5 bxa5
4. b5 axb5
5. cxb5 Ke7
6. b6 Kd7
7. g5 fxg5
8. b7 Kc7
9. h5 gxh5
10. f5 Kxb7
11. f6 g4
12. f7 h4
13. f8=Q
And the main reason why computter programs
like Wolf, Fritz und Adolf usw are having trouble
with this position is that the white king here acts
just like Winston Churchill. He just sits in his armchair,
smoking his cigar and drinking whiskey not careing about
how many white soldiers will die, as long as he has one left.
And one last thing:
The endgame tablebases that Kramnik was so afraid of
never comes to any use with so many pawns left as here.
Mr Hyatt must have put something new in his
evalu8pawnstructurefunc. (It was a Winboard precompiled
Crafty 19.19 that i left running for a while.)
PS
Thank you Susan your mindboggeling blogging.
It is nice to be back at the blog after beeing
sober and pretending to do some work for a while.
I’ll sure have some catching up to do
– now starting with all the beautiful pictures.
And if yo do not drop a line in here, my new computer
will Morph your four best official pictures of yourself with
all four versions of Edvard Munch “Skriet”.
http://sv.wikipedia.org/wiki/Skriet
forgot to tell
QM1 Todd R. Forbes (US Navy Retarded)
that this is a simple Double Sidewinder attack, best suited for the Swedish Airforce. (not even using our afterburners)
So stay put with your flagship, or go to rest in harbour. And I’ll bet you that any old russian fishingbout could also solv this problem whith a little help of rocketscience.
So, may GOD shave our Queen.
Lord Nelson
interesting double offers on a5 and h5. those were the moves that won it for white. as a checker player i understand all to well how those double offers wreak havoc. yea what i meant was ke7 but it obviously doesnt make a difference whether the e or c pawn for black takes whites d5 pawn .
wolverine
Well I set the computer to play black and myself white.
over the last few days I made many attempts to solve. Lots of losses and draws, but after 33 moves white checkmates.
I am sure it can be acheived in fewer moves, however, nice to solve.
White does not win! After
1. d5 cxd5
2. a5 bxa5
3. b5 axb5
4. cxb5 Ke7
5. b6 Kd7
6. exd5 next is 6…e5!
7. g5 hxg5
8. f5 gxf5
9. h5 a4
10. Ke2 a3
11. b7 Kc7
12. h6 a2 and Black queens first!
White WINS with:
1. d5 cxd5
2. a5 bxa5
3. b5 axb5
4. cxb5 Ke7
5. b6 Kd7
6. g5 fxg5
7. h5 gxh5
8. f5 a4
9. b7 Kc7
10. f6 Kxb7
11. f7 a3
12. f8=Q a2
13. Qg7+ Kc6
14. Qd4 dxe4
15. Qxe4+ Kd7
16. Qa4+ Ke7
17. Qxa2 h4
18. Qa7+ Kf6
19. Qd4+ Kf5
20. Qxd6