1. A6 Kc8 (otherwise a6 pawn will be Q) 2.Ne7 kb8 (same reason as no.1) 3.Nc6 Ka8 or kc8 then white king will go all up to b5 black can only move his bishop otherwise pawn will be promoted. then Nd8 then going to Nb7 (if Nd8 was guarded by bishop then either c5 or bishop is free)
if black king is not in a7 then Nc4 will give white advantage and win. else black king is in a7 then if B in d6 NxBd6 pxNd6, Kc6 — white wins
else if bishop is supporting c5 then white Kxc6 Kx16, Kxc7 … white will go to Kc6 and will have take the other pawn — white wins
1. Nb4 cb4 2. c5 Kc8 3. c6 draws because of 3… Kb8 (or 3…b3)
The correct solution is
1. Ne7 (threatens a6) c6 2. Nxc6+ (2. a6? Kb8!) Kc7 3. Nxb4 cxb4 and now, the thematic 4. c5 does the job. The two pawns protect indirectly each other: 4…Kc6 5. a6! and the white King has the time to gobble the pawn b4 and to sustain a pawn for queening.
Ne7 looks strong.
not good too ending but ne7 vom too me immediately ke7 a6.Ba5 nc6 chess
hey
Not good too ending but this com immediately ne7 if ke7 a6. Ba5 nc6
hey
Not good too ending but this com immediately ne7 if ke7 a6. Ba5 nc6
hey
Not good too ending but this com immediately ne7 if ke7 a6. Ba5 nc6
hey
Not good too ending but this com immediately ne7 if ke7 a6. Ba5 nc6
hey
I’m usually wrong on these things, but I would 1. Nxb4 cxb4 2. Kc2, followed by 3. Kb3.
On second thought, 1. Nxb4 cxb4 2.c5 looks better, followed by king going after the b-pawn.
The answer made me laugh.
maybe Ne7
h
Ne7!
If Kxe7, then the a-pawn cannot be stopped from promoting.
If Bxa5, then Nc6+ wins the bishop.
ne7 looks good
1. Nb4 cb4
2. c5 c6 (Kc8 3. c6 wins)
3. Kc2 Kc7
4. Kb3 Ka6
5. Kb4 wins.
Looks like Ne7 does the trick. If black captures the knight the a pawn promotes. The only way to stop the pawn is Ba5 in which case
1. a6 Bb6
2. Nc6+ Kd7 (or any other)
3. a7 Bxa7
4. Nxa7
and white wins.
Different solution from last time you posted this problem? 🙂
Ne7
if KxN, then the pawn marches
if BxP, then N fork
1. A6 Kc8 (otherwise a6 pawn will be Q)
2.Ne7 kb8 (same reason as no.1)
3.Nc6 Ka8 or kc8 then white king will go all up to b5 black can only move his bishop otherwise pawn will be promoted. then Nd8 then going to Nb7 (if Nd8 was guarded by bishop then either c5 or bishop is free)
if black king is not in a7 then Nc4 will give white advantage and win. else black king is in a7 then if B in d6 NxBd6 pxNd6, Kc6 — white wins
else if bishop is supporting c5 then white Kxc6 Kx16, Kxc7 … white will go to Kc6 and will have take the other pawn — white wins
otherwise Nxc5 white advantage and wins
— kiokups
For one time, Yancey Ward is wrong:
1. Nb4 cb4
2. c5 Kc8
3. c6 draws because of
3… Kb8 (or 3…b3)
The correct solution is
1. Ne7 (threatens a6) c6
2. Nxc6+ (2. a6? Kb8!) Kc7
3. Nxb4 cxb4
and now, the thematic
4. c5 does the job. The two pawns protect indirectly each other:
4…Kc6
5. a6! and the white King has the time to gobble the pawn b4 and to sustain a pawn for queening.
(August, source and date unknown)