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1.Rg8+ Kh6
2.Rf7 Rc7
3.Rxc7 Bd7
(3…. Bf5 4.Rh7+ Bxh7 5.Nf7#)
4.Rxd7 any
5.Rh7#
Remember seeing this some time ago!
1.Rg8+!.Kh6.
2.Rf7! Threatening 3.Rh7#
A>2….Bf5.3.Rh7+!.Bxh7.4.Nf7#!!
B>2….Rc7.3.Rxc7.Bf5.4.Rh7#!.Bxh7.5.Nf7#!!
C>2….Rd4+.spite check.3.cxd4.Bf5.(any other move.4.Rh7#!).4.Rh7+!.Bxh7.5.Nf7#!!
D>2….~ other.3.Rh7#!!
Beautiful N mate!
1. R1f7 Rd4+ 2. cxd4 Bf5 3. Rg8+ Kh6 4. Rh7+ Kh6 5. Nf7#
1. Rg8+ Kh6
2. Rf7! Rd4+ (Bf5 Rh7+ is one move faster)
3. cxd4 Bf5 (only against Rh7#)
4. Rh7+!!
The hard move to find. Note that Rxf5?? looses to a1=Q.
4. … Bxh7
5. Nf7#
It will be interesting to see how many find the wrong solution this time.
1. R1f7 Rd4 2. cd Bf5 3. Rg8 Kh6 4. Rh7 Bh7 5. Nf7#
Rg8 is the right first move. R1f7 leads to a mate in 6 with most resistant play.
To Yancey Ward:
What is the wrong solution here?
Another question: Is there a difference between 1. Rg8+ or 1. Rf7 as first move?
I couldn’t find the difference here, but ususally there is, and starting with a check is almost always safer….
Also, there seems to be 3 equivalent ways for black to delay it to become 3+2=5 moves:
a) Rc7 and Bd7
b) Rc7 and Bf5
c) Rd4+ and Bf5
Could be a total of 6 equivalent 5 move lines as far as I see.
What have I missed here?
pht,
1.Rg8 leads to mate in no more than 5 moves in all lines. However, 1.R1f7 leads to mate in 6 moves. I will borrow Oleg’s line from above:
1. R1f7 Rd4 (Rf6 is a 6 mover too)
2. cd4 Rf6
This is the move that is overlooked in the line. It is a sacrificial delay that costs white one move. Now, Rg8 is met by Kf5. White must waste the move to take the rook first, which then cost another move by making Rg8 not possible later:
3. Rf6 Kg7
And now Rg8 can’t be played yet. Either rook can come to f7 to mate, the shortest now is….
4. R8f7 Kh8
5. Rg6 with Rh7# on the next and 6th move.