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Q x N ch, then one of the two knights checks on F7, the other comes and it’s mate.
1.Qxh7+ Qxh7 2.Nf7+ Nxf7 3.Nxf7+mate
1qxn 2nf7 3nf7 smothered mate
1.Qxh7!! and mate with knight on f7,it is a mate in 3!
1. Qh7:+ followed by a smothered mate from f7.
Qh7+ followed by Nf7+
1. Qxht+ Qxh7
2. Ng(e)f7+ Nxf7
3. Nxf7#
1)Dxh7!, …Dxh7 2)Cf7+ Cf7 3)Cf7++
1 Qxh7+, Qxh7 2 N(either)f7+, Nxf7 3 Nf7#
1.Qxh7+…Qxh7
2.Nf7+…Nxf7
3.Nf7mate
1. Qxh7+ Qxh7
2. Ngf7+ Nxf7
3. Nxf7#
too easy.
just as a hint, for a moment I thought there were 2 winning moves for white
1. Nxh7 Qxh7 2. Ng6#
Yes, definitely easy.
1.Qh7 Qh7
2.Ngf7 Nf7
3.Nf7#
too obvious indeed 🙁
1.Qxh7 Qxh7 2.N( doesnt matter which one) f7+ Nxf7 3. Nxf7#
@anonymous (Nov 4 2010 11:01:00AM CDT): Wrong.
1. Qxh7+ Qxh7
2. Nf7+ Nxf7
3. Nxf7 checkmate.
For your move, Nxh7 Qxh7, Ng6 will be countered with Bxg6. U forgot the bishop I guess. 🙂
queen sac, then knights to f7
Fuzzylogic
Obvious may be but also wrong.
After Nxh7 black can move the rook to free a square for the king.
Better:
N(e5()f7+ NxN
Qxh7+ QxQ
NxN++
1.Qxh7+ Qxh7 2.Nf7+ (It doesn’t matter which one) Nxf7 3.Nxf7#
1.Qxh7+ Qxh7 2.Nf7+ (It doesn’t matter which one) Nxf7 3.Nxf7#
Nice but easy:
1. Qxh7+ Qxh7 2 Nf7+ Nxf7 3.Nxf7#
Actually 1. Nxh7 Qxh7 2. Ng6# is wrong, instead of Qxh7 black can move the rook on g8 and create an escape route for the king.
Correct solution: 1. Qxh7+ Qxh7 2. Ngxf7+ Nxf7 3. Nxf7#
Anon: 1. …Qxh7 isn’t forced. What about 1. Nxh7 Bf6+ ?
Qxh7 followed by twice Nf7
Who said black has to recapture the knight after Nxh7? What about Nxh7 Bxe5+?
It’s mate in 3 with Qxh7+ Qxh7, Ngf7+ Nxf7, Nxf7#
Qxh7 followed by twice Nf7
WRONG.. WHAT IF FOR Nxh7 – Bxe5 THEN?
Correct answer is
1. Qxh7 Qxh7
2. Ngf7+ Nxf7
3. Nxf7#
I notice a lot of posters using the term “obviously” when giving solutions to these problems. Is this really necessary? Even for the easier problems, I’m sure there are novices/beginners out there who don’t see the correct move. Why make them feel stupid?
End of rant:)
Try this:
1. Qh7+, Qxh7
2. Nf7+, Nxf7
3. Nf7# (black King smothered)
Maybe not so easy:
1. Nxh7 Qxh7 2. Ng6#
fails to 2…Bxg6
I think White must deflect the queen from the f7 square. Start with Rxd3, steal a pawn. If 1…Bxd3, then 2. e4 and the queen is in trouble. If black doesn’t take the rook then white can just keep piling on the pressure with, say, dxc6.
1. Qxh7 Qxh7
2. Nf7+ Nxf7
3. Nxf7#
1.Nxh7 ? Qxh7
2. Ng6 Bg6
1 Qh7+ Qh7
2 Nf7+ Nf7
3Nf7++
This a variation of the smother mate.
1.Qh7+ Qh7
2.N(e)f7+ or N(g)f7+
2…Nf7
3.Nf7#
Hello
It’s very easy
1. Qxh7+ , Qxh7+
2. Nef7+ or Ngf7+, Nxf7
3. Nxf7#
Greetings from Spain
I think
Qxh7 followed by
Nf7 mates.
1.Qxh7
“1. Nxh7 Qxh7 2. Ng6#”
Careful, that Bishop on e4 is allowed to move backward! It ain’t mate!:
2. … Bxg6 -+
Mating in three is:
1. Qxh7+ Qxh7
2. Ngf7+
( or 2. Nef7+ Nxf7 3. Nxf7#)
2… Nxf7 3. Nxf7# 1-0
Two good old Philidor’s legacy mates, but by a different route.
…
Since I do not see the answer yet:
1. Qh7 Qh7
2. Nf7 Nf7
3. Nf7#
For 2, it does not matter which knight.
Qxh7# hits the nail.
1. Qxh7 Qxh7
2. Ngf7 Nxf7
3. Nxf7#
mate in 3:
1. Qxh7+ Qxh7
2. Nf7+ Nxf7
3. Nxf7#
at least the annotation of the moves looks quite funny. jan
1.Qxh7+ Qxh7 2.Nef7+ Nxf7 3.Nxf7# White WON – KNOCKOUT2010