Thursday chess challenge

9 comments

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  Anonymous says:

  July 7, 2011 at 6:45 pm

  Bxb3 Nxb3 Rxa2

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  Yancey Ward says:

  July 7, 2011 at 6:55 pm

  At first I was sure I was going down the wrong path but felt obligated to try out the obvious Rh7+ anyway, but got a surprise once I reached the critical position:

  1. Rh7 Kg5
  2. f4 Kf6

  And it was here that I expected to find the dead end that would require a backtrack to move 1, but just as I was about to give up, I finally noticed that the seven rank is gone for black, and if white retreats the bishop somewhere safe, so is the sixth rank, with the threat of Ra6 followed by mate. So, where to put the bishop? The obvious square seems best:

  3. Bd5

  This carries a double threat, Ra6 followed by mate and either rook to f7 followed by mate. There is no defense against both threats.

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  fab says:

  July 7, 2011 at 7:06 pm

  1. Rh7+ Kg5
  2. f4+ Kf6
  3. Bd5
  threatening both Rf7+ Rxf7 Rxf7#
  and Ra6#
  e.g.
  4. Nb7 Rxb7
  or
  4. g5 Rh6#

  1-0

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  cheska says:

  July 7, 2011 at 7:16 pm

  1.Rh7+ Kg5
  2.f4+ Kf6
  3.Bd5 Nb7
  [if ..c1=Q 4.Ra/Rhf7+ Rxf7 5.Rxf7#]
  [if ..Rf7 4.Rxf7#]
  4.Raxb7 c1=Q
  5.Rb6+ Qc6
  6.Rxc6# ..it’s a cinch! lol

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  Anonymous says:

  July 7, 2011 at 7:21 pm

  1.f4! g5 (1…c1=Q 2.Rh7#)
  2.Bxb3 (threat of Re6+ Rf6 Rxf6+ Kh5
  Rh7#)
  2….gxf4+
  3. Kh4! (3.Kxf4? c1=Q+)
  3….Kg6 (3..Rf6? 4.Rf7+ Kg6 5.Rag7#)
  4.Ra6+ Rf6
  5.Bf7+ Kg7
  6.Bh5+

  6…Kg8 or Kf8 7.Re8#
  6…Kh6 7.Rxf6#

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  Lucymarie says:

  July 7, 2011 at 7:29 pm

  {Pretty simple, once one realizes that it is OK to let the Black king “escape” to f6. He can be mated there.}
  1. Rh7+ Kg5 2. f4+ Kf6 3. Bd5 Nb7
  (3. .. c1=Q 4. Raf7+ Rxf7 5. Rxf7#)
  4. Raxb7 c1=Q 5. Rb6+ Qc6 6. Rxc6#

  Lucymarie

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  aam@fics says:

  July 7, 2011 at 7:36 pm

  1. f4

  if 1… Ra8
  2. Bg8 g5
  3. Ra6#

  if 1… g5
  2. Bxf5 gxf4+
  3. Kh4 Rxf5
  4. Ra6+ Rf6
  5. Rxf6#

  or if 1… g5
  2. Bxf5 Rxf5
  4. Ra6+ Kh5
  5. Rh7#

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  Anonymous says:

  July 8, 2011 at 4:10 am

  1. f4 g5
  2. Bxf5! gxf4+
  3. Kh4! Rxf5
  4. Re6+ Rf6
  5. Rxf6#

  if 2…..Rxf5
  3. Re6+ Kh5
  4. Rh7#

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  prof.S.G.Bhat says:

  July 8, 2011 at 10:50 am

  1Rh7+ Kg5
  2f4+ Kf6
  3Be5 Nb7
  4Raxb7 c1=Q
  5any Rf7+ Rxf7
  6Rxf7#
  I prefer this to 5Rc6+ as I would the newly born black beauty queen to remain alive.