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1. f3
Threatening Rh7# and g4#.
1. …. exf3
2. Kh3
Now, no way for black to stop both Rh7# and g4#.
1. f3 exf3
2. Kh3 fxg2
3. Rh7#
Here is what I found on my own :
1) Rxh7+ ; Kg4
2) Rf7… and now black can only delay mate
2) … ; Rf6
3) Rxf6 ; a1=Q
4) Rf4+ ; Kh5
5) g4 mate
Later on, while verifying my analysis with a computer, I discovered that there is a quicker way to mate, but I’ll leave that for others to explain.
f3
1. Kh3 followed by g4#
1.f3, threat mate Rxh7 or g4, if 1…exf3 2.Kh3, same threat mate..By Tsekmate
Kh3, with mate to follow at g2-g4++
Black cannot prevent the mate.
1. f3 threatens both g4# and Rxh7#.
After 1. .. exf3 2. Kh3 renews both threats, and Black can only defend against one or the
other, not both.
If 2. .. fxg2 3. Rxh7#
Or if 2. .. Nxa7 3. g4#
Lucymarie
A simple puzzle but you still have to be careful. But another one in less than a minute.
At first glance a7*h7+but then the King escapes at g4.
So then one plays f2-f3 instead to stop the outlest and it runs:
1. f2-f3, e4*f3
2. and now the key is of course that the R is en prise at a7 so not g2*g3???? as b5*a7. Of course, the pawn move was also to prevent black’s c6*c3+ if one played Kh2-h3.
So now the full sequence is obvious:
1. f2-f3, e4*f3
2. Kh2! N*a7 or any other move
3. g2-g4 mate.
Psyche
1.Kh3
and 2.g4 or 2.Rxh7#
Almost too easy.
1. Kh3!
Threats both Rxh7# and g4#, black can’t survive this.
1. … Rxc3+ (only move)
2. f3 Rxf3+ (only move)
3. gxf3 Nc7 (delay)
4. Rxc7 h6 (only move)
5. Rh7! a1=Q (or any)
6. Rxh6#
1. Kh3 Rxc3+
( 2… Rc7 3. g4# )
2. f3 Rxf3+
( 2… exf3 3. g4#)
3. gxf3 a1=Q
4. Rxh7#
Is it possible that this exercise has two solutions?
The straightforward
1.Kh3 Rxc3+
2.f3 Rxf3+
3.gxf3 h6
4.Rh7
but the contorted
1.f3!! is quicker
1…gxf3
2.Kh3 and the two threats g4# and Rxh7# cannot be parried simultaneously…
Rxh7 Kg4 / Rf7! (with Rf4 and g4 mat)
Rxh7+ – Kg4 / Rf7! (then Rf4 and g4 mat)
f3 I guess. With mate coming in g4 if black does anything else than exf3, like taking the rook or promoting the queen.
Now, if exf3 then Kh3 with double threat: Rh7# and g4# that black can’t stop at once. The f3 black pawn now blocks Rxc3+ and there is nothing to do anymore to prevent checkmate.
1.Rxh7+ Kg4 2.Rf7 Rf6
(2…a1=Q 3.Rf4+ Kh5 4.g4#)
3.Rxf6 Kh5
(3…a1=Q 4.Rf4+ Kh5 5.g4#)
4.Rf4 a1=Q 5.g4#
Haven’t seen this ‘review’ before.
Is it
1. Kh3 Rxc3+
2. f3 Rxf3+
3. gxf3 h6
4. Rh7
I’d play Kh3
1.f3 exf3 2.Kh3 and then 3.g4# or 3.Rxh7#. They cannot be simultaneously stopped.
I was among those who liked Kh3 best (only looked at that one).
Correct enough, but faster is:
1. f3! exf3 (now black has no delaying R check on c3)
2. Kh3 fxg2 (otherwise g4#)
3. Rxh7#
Kh3 and g4# next.
I was looking through the solutions and was surprised at the amount of people that claimed 1. Kh3 is a valid solution. In counterpoint, I offer this line
1. Kh3 Rc3+ 2. f3 Rxf3+ 3. gxf3 Nxa7, where white stands no better.
I didn’t see Rxc3+
But then you cannot play
1.Kh3 because after
1…Rxc3+
2.f3 Rxf3+
3.gxf3 Nxa7 is simply wining for Black
and not 3…Nc7 for sure ;o)
I’m sorry to say that Kh3 is not “correct enough”. In fact it loses outright :
1) Kh3 ; Rxc3+
2) f3; Rxf3+
3) gxf3…
Now notice that white no longer has a pawn on the g-file, so black doesn’t have to fear g4#. And after…
3) … ; Nxa7 (yes, white’s rook was en prise all along)
4) Bf6 ; e3…
Black winds up with a winning endgame.