After 13 rounds:
1-2 Karjakin, Caruana 7.5 /13
3. Anand 7.0
4-7. Giri, Nakamura, Aronian, Svidler 6.5
8. Topalov 4.0
| 1-2. | Caruana, Fabiano | gm | USA | 2794 | * | * | ½ | . | ½ | 1 | ½ | ½ | ½ | ½ | ½ | ½ | ½ | 1 | ½ | ½ | 7½ | |
| 1-2. | Karjakin, Sergey | gm | RUS | 2760 | ½ | . | * | * | 1 | 0 | ½ | ½ | ½ | ½ | ½ | ½ | 1 | ½ | ½ | 1 | 7½ | |
| 3. | Anand, Vishy | gm | IND | 2762 | ½ | 0 | 0 | 1 | * | * | ½ | ½ | 1 | . | ½ | 1 | ½ | 0 | 1 | ½ | 7 | |
| 4-7. | Giri, Anish | gm | NED | 2793 | ½ | ½ | ½ | ½ | ½ | ½ | * | * | ½ | ½ | ½ | ½ | ½ | ½ | ½ | . | 6½ | |
| 4-7. | Svidler, Peter | gm | RUS | 2757 | ½ | ½ | ½ | ½ | 0 | . | ½ | ½ | * | * | ½ | 1 | ½ | ½ | ½ | ½ | 6½ | |
| 4-7. | Aronian, Levon | gm | ARM | 2786 | ½ | ½ | ½ | ½ | ½ | 0 | ½ | ½ | ½ | 0 | * | * | 1 | . | 1 | ½ | 6½ | |
| 4-7. | Nakamura, Hikaru | gm | USA | 2790 | ½ | 0 | 0 | ½ | ½ | 1 | ½ | ½ | ½ | ½ | 0 | . | * | * | 1 | 1 | 6½ | |
| 8. | Topalov, Veselin | gm | BUL | 2780 | ½ | ½ | ½ | 0 | 0 | ½ | ½ | . | ½ | ½ | 0 | ½ | 0 | 0 | * | * | 4 |
Final round 14 (March 28, 2016)
Svidler – Anand
Giri – Topalov
Nakamura – Aronian
Karjakin – Caruana
3. 7 Tie-breaks
If the top two or more players score the same points, the tie will be decided by the following criteria, in order of priority:
a) The results of the games between the players involved in the tie.
If they are still tied:
b) The total number of wins in the tournament of every player involved in the tie.
If they are still tied:
c) Sonneborn – Berger System.
3.7.1.a If there is no clear winner with the above 3 criteria, there will be a special competition between the players who still remain tied after using the 3rd criteria (Sonneborn – Berger): after a new drawing of colors, each tied player will play two (2) tie-break games with the other tied opponent(s). The games shall be played using the electronic clock starting with 25 minutes for each player with an increment of 10 seconds after each move.
Therefore, if Karjakin and Caruana tie for 1st, Karjakin would win because he has one extra win. However, if Karjakin, Caruana, and Anand tie for first, Caruana would win because he is +1 against Anand and ties 1-1 against Karjakin, while Anand is -1 against Caruana and ties 1-1 against Karjakin, and Karjakin ties 1-1 against both Anand and Caruana.
This is assuming that the final game are all drawn for these 3. Of course with 1 game left, anything can still happen.