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Mate in 2.
Definitely not a mate in two, but white loses the queen to prevent Qc1# on move 3. In the comments, whenever this is posted, there has always been disagreement about whether or not it is a proven forced mate. In my notes to the original posting of this in October of 2008, I wrote that the online analysis engines pegged a mate in 22 moves, but take that with a grain of salt- I really don’t remember writing that.
I think it’s a mate in 11. e.g.:
1. … Bxd3
2. Rxd3 Qc4+
3. Rc3 Qxe2+
4. Kb3 Rb1
5. Rc2 Qd3+
6. Rc3 Qd5+
7. Rc4 Qb7+
(7. Ka3 Qd2, 8. Rc2 Qxc2, 9. Kb4 Rxb2+, 10. Ka5 Qc5+, 11. Ka6, Qb6#)
8. Rb4 Qxf3+
(8. Kc2 Qxb2+, 9. Kd3 Rd1+, 10. Ke3 Qd2+, 11. Ke4 Re1#)
9. Ka2 Qd1
10 b3 Ra1+
11. Kb2 Qc1#
I didn’t find a better defense for white.
Excellent.
how about
3. Kd2 what’s the result on this line?
3. Kd2 Qc1#
Oh, yes, I recognize it Kramnik v Anand when Anand won the World Championship.
Darn! I spent time looking for a mate in 2 🙁
1. Bxd3+ Qxd3 2. Rg2+ Kc1 (.. Kb1 3. Qxb2# and … Kd1 3. Qg1+) 3. Qxb2+ Kd1 4. Rg1+ Qf1 5. Rxf1#
1. … Rxd3 2. Qc4+ Rc3 (… Kd2 3. Qc1#) 3. Qxe2+ Kb3 wins the queen.
Of interest is that Anand didn’t find 1.Bd3, but won the game anyway.
Here is a mate in 2, of course assuming white’s poor defence.
1. Qc4+
2. Kd2 Qc1 mate
1) … Qc4+ is a strong move, but it does not lead to mate. 2) Rc3 should hold. Now 2) … Qxa4+ also looks strong, since 3) b3, Qa2#, but 3) Rb3 prolongs the agony for a while, and better still, I certainly don’t see any quick mate if White instead tries 3) Ke2.