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1. Rf8+ N(or B)xf8
2. Qf7 mate
Slightly more than 5 seconds (you need a few seconds to look at the position)
2 sec
Puzzle for Alena:
8/8/8/4p3/4p3/R7/p2k1PK1/r7 b – – 0 1 black to move. Can black win this?
Yes. Black can win this. Here is the solution. It wasn’t very easy for me. The idea is obvious, but it requires solid endgame knowledge. I’m not sure I did it efficiently.
1…Kc2
2. Ra8 Kb2
3. Rb8+ Kc3
4. Ra8 Kb2
5. Rb8+ Kc3
6. Ra8 Kd4
7. Ra4+ Kc3
8. Ra8 e3
9. fxe3 e4
10. Rc8+ Kd2
11. Ra8 Kxe3
12. Ra5 Kd2
13. Ra4 e3
14. Rd4+ Kc3
15. Rd8 e2
16. Rc8+ Kb4
17. Rb8+ Kc5
18. Rc8+ Kb6
19. Rb8+ Kc7
20. Ra8 e1=Q
I didn’t see repeatitive moves.After the first move goes move 6.
I was wrong.
1…Kc2
2. Ra8 Kb2
3. Rb8+ Kc3
4. Ra8 Kd4
5. Ra4+ Kc3
6. Ra8 e3
7. fxe3 e4
8. Rc8+ Kd2
9. Ra8 Kxe3
10. Ra5 Kd2
11. Ra4 e3
12. Rd4+ Kc3
13. Rd8 e2
14. Rc8+ Kb4
15. Rb8+ Kc5
16. Rc8+ Kb6
17. Rb8+ Kc7
18. Ra8 e1=Q
I can’t say for certain this line is winning- it does seem to be a transposition of the the most efficient lines, but I would have to do some hard thinking to prove it right now. In any case, here is the link to the first time it was posted. Read the comments- particularly mine at the start and a couple later on, and those of a commenter named Cortex. Then at least reanalyze your plan above to determine whether or not you missed anything. If I have time later tonight I may sit down and work on your idea of 6. …..e3 and determine if it is too late or simply a transposition (I am leaning, right now towards it being a simple transposition).
Link
I looked through your link. It seems to me that my solution is transposition of your lines. There are two ways to win but your line is more efficient.
I looked through this again this morning, and I am now convinced that black can meander a bit before playing e3 and/or Kd1 followed by e3- it makes no progress to meander, but white’s position is so constrained, he can’t offer a defense that takes advantage of black’s meandering moves- unless black just blunders in dropping the a-pawn.
And if that one is too easy, then here is a nice little Mate in 3 by an anonymous composer:
4n3/K7/N2B4/pk1bP3/3R4/1P1P4/8/8 w – – 0 1
To my surprise I solved it very fast. Here is the solution.
1. Rc4 Bxc4
2. dxc4+ Kc6
3. Nb8#