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Rdb8 and the Queen is trapped
Reb8
1. … c4! 2. Bxc4 (2. Bc2/b1 Reb8 wins Queen) Qc5+ wins Bishop.
The 1979 must have thought he was doing quite well! But….
1….c4
if 2.Bxc4 Qc5+ wins B
if 2.Bc2/b1 R(f)b8 gets Q
(if 3.Nb5 Qc5+ and Rxb7)
0-0-0
-0-0-
1… c4!!
and now
A.
2.Bxc4? Qc5+ and the bishop is gone…
B.
2.Bc2? (or Bb1?) Rb8!! and the queen has nowhere to go and must be exchanged for either the rook or the bishop.
1…..c4 is a killer!
I think so 1…c4 2. Bxc4 qc5+ (2.bc2
or anywhere then 2….reb8 would
trap the queen. Even conter attack by
3. e5 can be dealt by 3…. Qc5+)
3. Kh1 qxc4 because early
1….Reb8 can be dealt by 2.qa6.
I also first looked to the queen trap, but the problem is that black’s own queen enforces the trap by covering a6, and this leaves white with three options- attack the white queen with 2.e5, 2.Nb5, or retreat with 2.Qa6. In none of those, does white lose major material as far as I can tell.
Looking at the queen trap wasn’t totally worthless- it induced me to look at c4, and once I did, could see black winning a piece for a pawn:
1. …..c4
2. Bc4
If white retreats the bishop, then 2. …Reb8 does trap the queen. Continuing:
2. …..Qc5
3. Rf2 Qc4
White was already up a pawn, so it is a bishop for two pawns at this point.